# 229 Y-coordinate of the point of application of the force

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## Comments

## How did you get 2/Sqrt13 as

How did you get 2/Sqrt13 as the dimension in y direction?

## You have to break down the

You have to break down the Force F into its components: Fx and Fy. Arrow F has a 2:3 slope ( count the number of squares). Its hypotenuse by P-theorem is the square root of 13. To resolve Fy you have to multiply F with 2/square root of 13. Hope this helps.

## The slope appears to be 2:3,

The slope appears to be 2:3, but that information is not provided in the problem statement or the diagram, so the solution uses an unjustified assumption.